Triangle - Triangle
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Triangles are one of the most important topics of mathematics. It studies the similarity of shapes, various theorems detailing a similar relationship between the two triangles. These theorems apply to every type of triangle, starting from an isosceles to a right-angled triangle.
The following conditions for similar triangles, various similarity criteria theorems of triangles, and results derived from these criteria need to be understood and remember:
Similar Figures
Source: NCERT
Similar Triangles
Two triangles are said to be similar if:
Various Criteria for Similarity of Triangles
Two triangles are similar; if the two triangles' corresponding angles are equal, then their corresponding sides are in the same proportion.
If the two angles of one triangle are equal to two angles of the other triangle, both triangles are similar.
Two triangles are similar; if the corresponding sides of two triangles are in the same proportion, their corresponding angles are in the same ratio.
Two triangles are similar if one angle of a triangle is equal to the one angle of another triangle, and sides including these angles are in the same proportion.
Results derived from Similarity Criteria Theorems
A triangle is a geometrical figure comprising three vertices and three sides. The sum of all angles in a triangle is 180 degrees, and this is the fundamental property of this three-sided figure.
Properties of a Triangle
The important properties of a triangle, as stated below:
Types of Triangles
Based on its sides’ length, a triangle has three types, viz. scalene, equilateral and isosceles triangle. Based on the measurement of its angles, a triangle has three types, viz. acute-angled triangle, obtuse-angled triangle, and right-angled triangle.
Based on the sides
Based on the angles
Area & Perimeter of a Triangle
The area of a triangle can be measured by multiplying the product of its base and height by half.
Area of a triangle = ½ x base x height.
The perimeter of a triangle is equal to the sum of its all sides.
Heron’s FormulaIf the length of all the sides of a triangle is known, then its area can be measured by using Heron’s formula which says that area of a triangle ABC = √[s(s-a)(s-b)(s-c)], where s = perimeter of the triangle.
Weightage of TrianglesThis is an important chapter in class 10. 8-10 marks are allotted to this chapter. A student may expect 1 mark, 2 marks and 3 marks questions from this chapter.
Illustrative Examples on Triangles1. A 6.5 m long ladder is put against a wall so that its foot should rest at a distance of 2.5 m from the wall. Find the height of the wall where the top of the ladder touches it.
Solution: Let AC be the ladder and AB be the wall.Given: AC = 6.5m =13/2 mBC=2.5 m= 5/2m In Right angle triangle, ABC,
AB2 + BC2 = AC2 (By using Pythagoras Theorem)
AB2+ (5/2)2 = (13/2)2
AB2= 169/4 – 25/4
AB2 = 144/4 = 36
∴Required height, AB = 6 m
2. If a line segment intersects sides AB and AC of an ∆ABC at D and E respectively and is parallel to BC, prove that AD/AB=AE/AC.
Solution:Given: In ∆ABC, DE || BC
To prove: ∆DAB=∆EACProof: In ∆ADE and ∆ABC ∠1 = ∠1 … Common∠2 = ∠3 … [Corresponding angles]∆ADE ~ ∆ABC [AA similarity criteria] ∴ AD/AB =AE/AC [In similar ∆’s corresponding sides are proportional to each other.]
3. If PQ || RS, prove that ∆POQ ~ ∆SOR.
Solution:PQ || RS (Given)
Source:NCERTSo, ∠ P = ∠ S (Alternate angles) ∠Q = ∠ R ∠∆POQ = ∠∆SOR (Vertically opposite angles) Therefore, ∆POQ ~ ∆SOR (AAA similarity criterion)
4. The height of a triangle is 30cm and its base measures 45 cm. Find its area.
Solution:
Area of a triangle = ½ x base x height = ½ x 30 x 45 = 675 square cm.
5. The perimeter of an equilateral triangle is 120 cm. Find its area.
Solution:
In an equilateral triangle, each side has the same length. Therefore, if we consider each side to be of length x, then the perimeter can be given by:
3x = 120.
Therefore, x = 40.
From Heron’s formula the area of the triangle will be:
= √[s(s-a)(s-b)(s-c)]= √[ 120 (120 - 40) (120 - 40) (120 - 40)]= √[120 x 80 x 80 x 80]= 5608679 square cm.
6. In triangle ABC, AB = 5cm and BC = 7cm. Find the length of its other side if its perimeter is equal to 15cm.
Solution:
Perimeter = sum of all sides = AB + BC + AC
15 - (5 + 7) = AC
Therefore, AC = 3 cm.
FAQs on TriangleQ: What is Thales Theorem?
A: Thales stated that if a line is drawn parallel to one side of a triangle intersecting the other two sides in distinct points, then the other two sides are divided in the same ratio.Q: What is the converse of the Triangle Proportionality Theorem?
A: The converse of Thales theorem states that "A line drawn to cut two sides of a triangle in equal proportion is parallel to the third side."Q: Explain Angle Bisector Theorem?
A: The internal or external bisector of an angle of a triangle divides the opposite side internally or externally in proportion to the corresponding sides, including the angle.Q: Explain Pythagoras Theorem?
A: In a right triangle, the hypotenuse square is equal to the sum of the squares of the other two sides.Q: Explain Converse of Pythagoras Theorem?
A: In a triangle, if the square of one side is equal to the sum of the other two sides’ squares, then the angle opposite the first side is a right angle. Dates Section:| Domain | national |
| Exam Type | preparation |
| Is Conducting Body | No |
| Is Exam Paid | 0.0 |
| Is Abroad | 0.0 |
| Abbreviation | Triangle |
| Is Abroad | 0.0 |
| Exam Year | 2021 |
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